y^2-33y+32=0

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Solution for y^2-33y+32=0 equation: 



y^2-33y+32=0

a = 1; b = -33; c = +32;
Δ = b2-4ac
Δ = -332-4·1·32
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-31}{2*1}=\frac{2}{2}
=1
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+31}{2*1}=\frac{64}{2}
=32
$

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